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CGP EDU Academic Team
Published on: September 12, 2026
The resultant of \vec{A} + \vec{B} is \vec{R}_{1} On reversing the vector \vec{B}, the resultant becomes \vec{R}_2. What is the value of \(\mathbf{R}_1^2 + \mathbf{R}_2^2\)
Text Solution
Verified by ExpertsThe correct answer is:
C
\vec{R}_1 = \vec{A} + \vec{B} , \vec{R}_2 = \vec{A} - \vec{B}
\(R_1^2 + R_2^2 = \left(\sqrt{A^2 + B^2}\right)^2 + \left(\sqrt{C^2 + D^2}\right)^2\) = 2(A^{2} + B^{2})
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